If we close the Scanner object, it will close the input stream too, and now if we want to open it again, then it is not possible, so it is better not to close the scanner object till the end of the program. Normally it stays open throughout the life of the program. When we create an instance of the Scanner class, we give “ System.in” to its constructor for opening the input stream. It’s better to close the Scanner object at the end of the program. ('Marks of Roll number '+rollno+' is: '+marks) Marks = Integer.parseInt(input.nextLine()) Rollno = Integer.parseInt(input.nextLine()) Now, look at this example which explains how to remove this error from our code. nextLine() method returns a string, and if we want to store it in a string, then we have to convert it. Using nextLine() solves our program error, but it is better to write nextLine() in place of nextInt() and convert it to int. If we want to eliminate this exception, we must write nextLine() after each input method, like nextInt(), etc. If we take input from the user with methods like nextInt(), nextFloat or nextDouble(), etc, without using nextLine() after each input, these methods consume the remaining that’s why we face the exception No line found. Use hasNextLine method to check the next lineĬase 2: Using methods like nextInt() or nextFloat() with nextLine() String str = 'Zeshan Java Developer' Now let’s explain the checking method hasNextLine() with the help of an example: You should only move to the next position if the check returns that the position is not empty. The solution to : No line found exception is to check whether the next position of a scanner object is filled or empty. Now let’s see the detail of the following solutions one by one:

Use method like nextInt() and nextDouble() with nextLine().

We can fix : No line found with the help of the following ways: Now let’s move forward to its solution without any further delay.

Create another object of Scanner Class after closing the previous one.

Using methods like nextInt() or nextFloat() without nextLine() or parsing.

Not checking the next position of the scanner object.

Two most common reasons for Exceptions in thread “main” : No line found are the following: It is a text Scanner and a class in java.util package that obtains the input of the data types like int, double, and strings.

In Java, Scanner is one of the easiest ways to take input from the user’s runtime or read input. What is a Scanner in Java and Why do we Use it? ('Enter your Roll number:') īefore we move forward to the solution to this problem, we must know about the scanner and the situations when and why we use it. Now understand another situation when a No line found error occurs. If you are using an older version of Java, then you will face this exception in the case of nextInt() method. String s = 'Zeshan Java Developer' The error will occur when we use the method without maximum limits. The error : No line found occurs when we are using a Scanner object to get input from the user or printing string on screen with the help of methods like nextLine(), nextInt(), or any other scanner built-in methods. The Java Virtual Machine ( JVM ) raises this exception when we use methods like nextLine(), nextElement(), nexttoken(), etc.

Classes like Enumerator, Scanner, or StringTokenizer throw this runtime error. It is an unchecked exception (Also known as runtime exception). NoSuchElementException extends RuntimeException, which is thrown when someone tries to access an element beyond its maximum limit. What is a Scanner in Java and Why do we Use it?.When Does the No Line Found Error Occur?.What is NoSuchElementException in Java?.

Jgrasp java no such element excpetion